It helps to understand this if you imagine putting the boy behind door 1, and then the other child behind door 2 or door 3, with the other door having a goat behind it.
This is on ITV from next Saturday, presented by Ant and Dec.
It helps to understand this if you imagine putting the boy behind door 1, and then the other child behind door 2 or door 3, with the other door having a goat behind it.
We know that there can't be two girls - BG and GB are both consistent with the information that at least one child is a boy, as is BB (but not GG).You know that one child can't be a girl so how can you have both GB and BG?
We know that there can't be two girls - BG and GB are both consistent with the information that at least one child is a boy, as is BB (but not GG).
Yes, we know there can't be two girls. However our real options, each of 50% probability are:
1- BB
2- A boy and a girl.
Yes, we know there can't be two girls. However our real options, each of 50% probability are:
1- BB
2- A boy and a girl.
Yes, we know there can't be two girls. However our real options, each of 50% probability are:
1- BB
2- A boy and a girl.
One is declared, but we don't know which one.
I may indeed have been captaining a failboat here.
One is declared, but we don't know which one.
I may indeed have been captaining a failboat here.
I could just delete the threadI have to make a fool of myself on Urban at least once a month.
It's a rule.
I could just delete the thread
I still think you're all thick.
If one is a boy, and he's the oldest one, the younger one is either a girl (BG) or a boy (BB)
Howver if he's the youngest one, the older one is either a girl (GB) or a boy (BB)
So BB is actually twice a likely as BG or GB, since the Bs can be in two different orders.
That gives our options, given one child is a boy, as BB, BB(with the Bs the other way round), GB and BG.
The other child is just as likely to be a boy or a girl
Get a deck of cards. Shuffle them, inverting each cut as you do, so that they are face up and face down, all intermingled.I still think you're all thick.
If one is a boy, and he's the oldest one, the younger one is either a girl (BG) or a boy (BB)
Howver if he's the youngest one, the older one is either a girl (GB) or a boy (BB)
So BB is actually twice a likely as BG or GB, since the Bs can be in two different orders.
That gives our options, given one child is a boy, as BB, BB(with the Bs the other way round), GB and BG.
The other child is just as likely to be a boy or a girl
I still think you're all thick.
If one is a boy, and he's the oldest one, the younger one is either a girl (BG) or a boy (BB)
Howver if he's the youngest one, the older one is either a girl (GB) or a boy (BB)
So BB is actually twice a likely as BG or GB, since the Bs can be in two different orders.
That gives our options, given one child is a boy, as BB, BB(with the Bs the other way round), GB and BG.
The other child is just as likely to be a boy or a girl
Oh shit.
The second part is not "What is the probability that the other child is a boy" but "What is the probability you have two boys?"
That's where we went wrong, LBJ.
Plane crashes into the mountain. No survivors.
how can the answer to these questions be different?
I still think you're all thick.
If one is a boy, and he's the oldest one, the younger one is either a girl (BG) or a boy (BB)
Howver if he's the youngest one, the older one is either a girl (GB) or a boy (BB)
So BB is actually twice a likely as BG or GB, since the Bs can be in two different orders.
That gives our options, given one child is a boy, as BB, BB(with the Bs the other way round), GB and BG.
The other child is just as likely to be a boy or a girl
That thread where we both shone like beacons of intellectual clarity and everyone else took ages to get it, which is a shame cos I accidentally deleted it.
What thread?
They're not. Crispy failed at explaining his fail.how can the answer to these questions be different?
but that's not the question being askedOk, say in all these two-child families, the second child was just oozing out of the flaps and hadn't revealed it's bits yet.
If the family already had a boy, would the doctor say "oooh it's just coming out but there's only a 1/3 chance it will be a girl I'm afraid, because I've excluded the GG combination already"
Ok, say in all these two-child families, the second child was just oozing out of the flaps and hadn't revealed it's bits yet.
If the family already had a boy, would the doctor say "oooh it's just coming out but there's only a 1/3 chance it will be a girl I'm afraid, because I've excluded the GG combination already"
Ok, say in all these two-child families, the second child was just oozing out of the flaps and hadn't revealed it's bits yet.
If the family already had a boy, would the doctor say "oooh it's just coming out but there's only a 1/3 chance it will be a girl I'm afraid, because I've excluded the GG combination already"
No, because that's an entirely different question. And that's the whole point of this puzzle. Just like the plane on a conveyor belt - you have to work out what question you're answering first.